Cisco 200-301 Practice Test 17
Question 160
A technician is auditing the operational state of an HSRP group on a Cisco IOS router. Which TWO verification statements correctly describe information exposed by the normal HSRP show commands? Choose TWO.
show standby brief can summarize local state, active and standby router identities, and the group virtual IPshow version proves that a device currently owns the HSRP virtual MAC solely from its license informationshow standby can report the configured HSRP virtual IP, hello and hold timers, and active/standby peer informationshow ip route alone always reports which neighboring router is the HSRP standby for each group- The HSRP virtual IP must be removed from both peers before
show standby can display group state - A switch MAC table listing the physical interface MAC of R1 alone proves R1 is HSRP active
Explanation
Correct Answers
A:show standby brief gives a compact Cisco HSRP group status view, including the local router's role and relevant active/standby peer identities or virtual gateway information on supported IOS releases. It is a useful first operational check to determine whether the device is active, standby or listening for a particular interface/group. The command observes protocol state rather than establishing it. If a value is missing, check the detailed group display and interface configuration.
C:show standby provides the detailed HSRP operational view and can display the group virtual IP, configured hello/hold intervals and active/standby information, depending on platform and HSRP version. Those values help diagnose role election, missed hellos and failover timing. It is a direct read-only verification method, not a replacement for checking actual forwarding and reachability. In combination with the brief summary it supports the stated operational audit.
Incorrect Answers
B:show version reports platform and software information such as IOS release, hardware and system uptime; its ordinary license fields do not establish which router currently owns an HSRP virtual MAC. HSRP active/standby ownership is dynamic and can change after link or device failure without changing the software image. The operator must inspect HSRP-specific state through show standby commands. A license summary is not an authoritative runtime gateway election report.
D:show ip route lists IPv4 destinations, route sources and selected next hops, but does not universally display the standby HSRP member for every group. An HSRP virtual gateway is a first-hop redundancy construct and may not be represented as a named backup identity in the routing table. A router could retain identical routes while HSRP ownership changes. Use HSRP-specific inspection to identify group roles rather than inferring them solely from route entries.
E:HSRP requires a configured virtual gateway identity for participating routers to advertise and manage the group; removing the virtual IP from both peers would undermine the intended service. show standby is designed to display current state while the virtual IP is configured, not only after it has been deleted. The proposed condition reverses the purpose of the command. Leave a working virtual gateway in place and inspect the group's current role and timers.
F:A conventional switch MAC table learns source MAC addresses on ingress interfaces and may list a physical router MAC as ordinary traffic is observed. That observation alone does not prove the same device currently owns the HSRP virtual gateway identity, which uses virtual MAC behavior tied to HSRP role and version. An active-to-standby transition may leave historical MAC-table entries temporarily. Verify the HSRP state using show standby rather than a single physical MAC entry.
Question 161
A wireless engineer needs an AP radio to capture 802.11 frames on a selected channel and forward those captures to a remote packet-analyzer workstation through controller-supported infrastructure. Which AP mode directly serves this task?
- Sniffer mode
- Local mode
- FlexConnect mode
- Root bridge mode
Explanation
Correct Answer
A:Cisco lightweight AP Sniffer mode can tune a radio to a specified channel, capture 802.11 traffic and stream that capture through a supported controller or capture infrastructure to a remote packet-analysis destination. This is suited to troubleshooting over-the-air management and data frames without treating the AP as a normal client-serving radio. Confirm controller and AP support as well as capture-channel configuration; the selected channel and destination must match the investigation.
Incorrect Answers
B:Local mode generally provides wireless service to associated clients while using controller-managed control and, in centrally switched designs, data paths. A Local-mode AP can perform certain background measurements, but its normal role is not a dedicated channel-specific full-frame capture stream to a remote analyzer. The request specifically involves sending packet captures off-site for analysis, which calls for the supported Sniffer function rather than standard client association mode.
C:FlexConnect is commonly used for branch or remote-site WLAN deployments and can locally switch some client data while retaining controller management. Its primary operational purpose is preserving useful client service and policy behavior across WAN designs. It does not inherently configure a radio for dedicated 802.11 packet capture and streaming to a remote analyzer. The requested forensic visibility is a specialized sniffer operation, not a client switching architecture.
D:A root bridge role is associated with bridging or spanning-tree topology functions, depending on the platform and technology, rather than the requested wireless frame-capture mode. Acting as a bridge moves frames between network segments but does not necessarily reproduce monitored 802.11 frames for a packet analyzer. The engineer wants capture on a chosen RF channel through controller-supported infrastructure, for which Sniffer mode is the direct match.
Question 162
The Cisco IOS routing table includes O 10.80.0.0/16 [110/23] via 192.0.2.9, 00:02:40, GigabitEthernet0/1. What does the displayed 00:02:40 field indicate for this route?
- The measured end-to-end packet latency to 10.80.0.0/16 is 2 minutes and 40 seconds
- The route entry was last updated approximately 2 minutes and 40 seconds ago
- The route was learned from OSPF area 2 with a 40-second dead interval
- The router will delete the route after 2 minutes and 40 seconds regardless of new updates
Explanation
Correct Answer
B:For a learned OSPF route, 00:02:40 in the IOS route display is the elapsed time since that routing information was last updated or installed, approximately two minutes and forty seconds in this example. The separate [110/23] bracket contains administrative distance 110 and OSPF cost 23. A healthy route can remain usable while its age increases; this display is diagnostic history, not an end-to-end latency metric.
Incorrect Answers
A:The time value shown after the next hop in an IOS route entry is not a measured packet round-trip delay or one-way latency. Router forwarding tables generally do not encode live application response time in that field. Latency must be measured with appropriate probes or telemetry, and it could differ from the route's age. The question concerns a normal show ip route entry and asks what its time notation represents.
C:An OSPF area is defined by the interface's OSPF area configuration and associated topology, not inferred by splitting the route-age clock into digits. OSPF Dead intervals are configured on participating interfaces and are normally displayed through OSPF interface commands. The [110/23] fields already indicate routing preference and metric, while 00:02:40 is a duration since update. Treating the clock as area and timer information confuses unrelated fields.
D:A route's displayed age is not automatically a fixed countdown until deletion irrespective of ongoing protocol advertisements. OSPF maintains reachability through neighbor state and link-state database updates; route withdrawal can occur when topology or protocol state changes. Seeing 00:02:40 does not imply precisely two minutes and forty seconds remain. The counter reflects elapsed update time, and its operational significance requires separate protocol and neighbor investigation.
Question 163
A branch workstation has 192.168.12.40/24 and can reach internal resources, but an engineer proposes advertising that private address unchanged as an Internet-reachable host address. Which statement best identifies the address-plan problem?
- RFC1918 192.168/16 source addresses are not globally routed as public Internet host destinations; the edge needs an appropriate public-facing addressing/translation design
- The 192.168 address automatically becomes globally unique if the DNS hostname has an A record
- Every 192.168/16 address is a multicast destination and cannot be used inside a LAN
- An RFC1918 address becomes public simply because the Ethernet access port uses VLAN 1
Explanation
Correct Answer
A:The IPv4 range 192.168.0.0/16 is reserved for private internetwork use, so 192.168.12.40 cannot be advertised as an ordinary globally routed public host destination without a suitable public-facing design. Enterprise edge devices may use source NAT/PAT for outbound access or a published public endpoint for services. A DNS name or working internal route does not change public address allocation. The private host can remain valid on the internal 192.168.12.0/24 network.
Incorrect Answers
B:DNS maps names to resource records and can return public or private IPv4 addresses, but it does not allocate public address ownership or change how Internet routers treat RFC1918 space. Publishing a hostname whose A record points at 192.168.12.40 would not make that private host universally reachable from the public Internet. The organization still needs a valid externally reachable address, firewall policy and potentially NAT or proxying. Name resolution and global routing are separate systems.
C:IPv4 multicast addresses are in 224.0.0.0/4, whereas 192.168.0.0/16 is RFC1918 private unicast space. The workstation's 192.168.12.40 address is perfectly suitable for internal LAN use and can be reached by appropriately routed private networks. Its limitation is global public Internet reachability without translation or other architectural support, not an inherent multicast property. Misclassifying it as multicast would also lead to incorrect LAN troubleshooting.
D:An Ethernet port's VLAN membership controls which Layer 2 broadcast domain carries a host's frames; VLAN 1 is not a public IPv4 allocation service. Placing 192.168.12.40 on VLAN 1 leaves the address private and does not make external routers accept it as an Internet-routable host. In fact, using VLAN 1 indiscriminately can weaken segmentation. The proper correction concerns public-facing addressing and routing policy at the network edge.
Question 164
An IPsec site-to-site tunnel uses ESP. What security service is ESP specifically intended to provide when encryption and integrity are correctly configured?
- Assigning a public DNS hostname to every inner host
- Replacing the need for source and destination routing
- Negotiating the Ethernet native VLAN on a campus trunk
- Confidentiality and integrity protection for selected IP traffic
Explanation
Correct Answer
D:Encapsulating Security Payload can provide confidentiality through encryption and can supply integrity and data-origin authentication when the selected IPsec algorithms and security associations support them. It protects the selected traffic as it crosses an untrusted site-to-site path, rather than advertising the private hosts publicly. Keys, algorithms, peer authentication and tunnel policy must be configured consistently. Encryption alone does not guarantee every possible traffic flow is covered; selectors and routing determine the protection scope.
Incorrect Answers
A:DNS hostnames provide human-readable names that resolvers can map to IP addresses when appropriate records exist. IPsec ESP does not assign public domain names to internal endpoints or require every encapsulated host to be individually exposed to the Internet. A site-to-site VPN can protect traffic between private subnets while gateway endpoints handle the outer transport addresses. The security service in question is packet protection, not application name registration.
B:ESP protects packets selected by IPsec policies, but the gateways still need routing and security associations that define where protected traffic travels. Encryption does not calculate destination next hops or replace the IP forwarding decision. A packet can be correctly encrypted yet fail if routes or tunnel reachability are wrong. The question is about the confidentiality and integrity services offered by ESP when configured appropriately, not automatic network-route discovery.
C:An Ethernet native VLAN determines how untagged traffic is handled on an 802.1Q trunk between Layer 2 devices. ESP operates at the IPsec layer to protect selected IP packets across suitable paths and has no role in switchport VLAN negotiation. A VPN gateway might carry ESP traffic through a VLAN, but that encapsulation does not configure the trunk. Conflating these controls would leave both the VLAN and VPN requirements improperly managed.
Question 165
A router learns reachability information using OSPF and then forwards packets using its installed forwarding table. Which statement correctly distinguishes control plane from data plane?
- OSPF route computation is control-plane work; forwarding packets from the installed table is data-plane work
- Both operations are exclusively part of the management plane
- The data plane performs all neighbor discovery while the control plane transmits user payloads
- Only northbound APIs can determine whether a packet is forwarded
Explanation
Correct Answer
A:OSPF discovers routing neighbors, exchanges link-state information and computes candidate paths, which are control-plane activities used to establish forwarding decisions. Once suitable routes and adjacencies are installed, the data plane uses forwarding entries to transmit ordinary user packets. A router can carry packets at high speed without running the full OSPF algorithm for every frame. Separating these roles helps operators diagnose route-convergence problems versus forwarding-path failures.
Incorrect Answers
B:The management plane includes operator configuration, monitoring and administrative access functions. OSPF neighbor formation and shortest-path computation belong to routing control, while transmitting user traffic using installed forwarding state belongs to the data plane. Both can be observed through management commands, but observing a function does not reclassify it as management-plane work. The scenario explicitly compares route computation and packet forwarding, which reside in distinct planes.
C:The data plane forwards packets according to selected lookup and adjacency information; it is not solely responsible for all routing neighbor relationships. The control plane instead learns and computes route state, including OSPF exchanges, rather than transporting each user payload itself. Some neighbor-resolution functions interact with several implementation components, but the proposed reversal of route learning and forwarding is incorrect. The data plane uses results produced by control-plane processes.
D:Northbound APIs may expose controller intent or services to an orchestration application, but a traditional IOS router can select and forward packets using local control- and data-plane state without such an API. Routing table entries, ACLs and forwarding adjacencies directly affect packet delivery. An API may configure those policies, not uniquely determine every packet's fate. The task asks for the conceptual separation of OSPF computation from actual packet forwarding.
Question 166
A Cisco IOS router must generate RSA key material for SSH. Which TWO prerequisites are commonly needed when using the traditional IOS RSA generation workflow? Choose TWO.
- A configured hostname
- A
switchport trunk allowed VLAN list - A configured IP domain name
- An NTP stratum explicitly set to 1
- An OSPF router ID equal to the management IPv4 address
Explanation
Correct Answers
A:In the traditional Cisco IOS RSA key-generation workflow, the configured hostname forms part of the fully qualified domain name used when generating and identifying key material. Setting a meaningful device hostname is therefore a common prerequisite before running crypto key generate rsa. Newer platforms may support different key-management workflows, but the question explicitly names the traditional one. Other SSH configuration, including user accounts and VTY authentication, still has to be completed.
C:A configured IP domain name is combined with the router's hostname for traditional IOS identity information when generating RSA keys for SSH. This supports the expected local FQDN context associated with that workflow. After configuring both parameters, generate a suitably strong key pair and verify the SSH server version and login policies. The domain name is not itself an authentication credential, but it provides an identity prerequisite for the classic command sequence.
Incorrect Answers
B:A switchport trunk allowed vlan list controls which VLANs traverse a tagged Ethernet trunk; it does not supply cryptographic identity parameters for an SSH server. The router might be reachable through a trunk, but its RSA key-generation procedure is independent of allowed VLAN membership. Configuring the trunk does not define the FQDN context that classic IOS key generation commonly expects. The necessary prerequisites are the local hostname and IP domain-name settings.
D:NTP stratum describes a device's time-source hierarchy and may help produce consistent security logs. RSA key generation does not ordinarily require that an IOS router be assigned stratum 1, and claiming otherwise confuses time-service configuration with cryptographic identity initialization. Accurate clocks can matter for certificates and event investigation, but they do not replace hostname and IP domain-name prerequisites in this specified workflow. Do not configure false primary time-source status merely to enable SSH.
E:An OSPF router ID is used to identify a participant in the OSPF routing process and should be unique within its routing domain. It need not equal the management IPv4 address and is not a traditional prerequisite for SSH RSA key generation. SSH keys rely on cryptographic and device identity configuration, not OSPF neighbor identity. The two features can operate independently; requiring equality would add an unnecessary and potentially misleading routing constraint.
Question 167
A router has routes to 10.0.0.0/8 and 10.50.0.0/16 but no default. It receives a packet to 198.51.100.15. What happens under normal IP destination-based routing?
- Forward using 10.0.0.0/8 because it is the broadest available route
- Flood the packet to every routed neighbor until one responds
- Drop the packet for lack of a matching route
- Send the packet through the VLAN with the lowest spanning-tree cost
Explanation
Correct Answer
C:Normal IPv4 forwarding uses longest-prefix matching among routes that actually contain the destination. Neither 10.0.0.0/8 nor 10.50.0.0/16 includes 198.51.100.15, and the router has no default route. There is therefore no eligible destination entry for forwarding, so the packet is dropped; the router may send an ICMP destination-unreachable message according to policy. This is a route-lookup failure, not an OSPF or Layer 2 problem.
Incorrect Answers
A:The route 10.0.0.0/8 matches addresses beginning with 10, but 198.51.100.15 is outside that prefix and also outside the installed 10.50.0.0/16 route. Routers cannot use the broadest available route for arbitrary destinations without a prefix match. A default 0.0.0.0/0 would be such a fallback, but the stem says none exists. Choosing 10/8 merely because it covers many addresses would violate normal destination-based routing.
B:IPv4 routers do not ordinarily flood unknown destination packets to every routed neighbor as Ethernet switches flood unknown unicast within a VLAN. IP forwarding depends on selecting an installed destination route; without a match or default, the router cannot identify a valid next hop. Broadcasting the packet across unrelated routed links would create severe scalability and loop problems. In this case the correct behavior is to discard the unmatched packet and potentially signal an unreachable condition.
D:Spanning-tree path cost determines loop-free Layer 2 forwarding roles among bridges, not how a router handles an arbitrary IPv4 address with no matching route. VLANs and STP can influence reachability of an Ethernet egress, but first the router must identify a destination route. The question explicitly provides two nonmatching IPv4 prefixes and no default; choosing a VLAN by cost would bypass routing logic and cannot solve the missing forwarding entry.
Question 168
A wireless LAN controller uses a platform-supported Link Aggregation Group to combine several controller uplink ports. How should the distribution switch normally treat those physical controller connections?
- Configure the switchports as unrelated VLAN access links with conflicting policies
- Configure a compatible switch-side EtherChannel/port-channel for the WLC LAG
- Bridge the controller’s serial console port into the data VLAN
- Enable OSPF on every WLC physical port instead of aggregating them
Explanation
Correct Answer
B:A controller Link Aggregation Group combines supported physical uplinks into a logical connection; the distribution switch normally configures a compatible Port-channel or EtherChannel and matching trunk/VLAN properties. That avoids interpreting bundle members as unrelated standalone links. The exact WLC model may specify whether the controller side uses LACP or a static LAG, so verify the documented mode before deployment. Consistent speed, VLAN policy and switch-side aggregation configuration are essential for reliable service.
Incorrect Answers
A:Unrelated access switchports normally each belong to one untagged VLAN and do not coordinate their bandwidth as a single logical controller uplink. Treating members of a WLC Link Aggregation Group as independent links with conflicting policies can break bundle formation, VLAN handling or client connectivity. The distribution switch should present the matching logical aggregation where the WLC and platform support it. Member characteristics must agree instead of being independently inconsistent.
C:A controller's serial console interface provides local administrative access and cannot be bundled into an Ethernet data VLAN with high-speed WLC uplink ports. It has different electrical signaling and protocol behavior from network Ethernet interfaces. Console access is important during recovery, but it is not part of the LAG forwarding path. The requested design concerns data-plane cable links between the WLC and distribution switch, not management serial cabling.
D:OSPF is a Layer 3 routing protocol and does not combine several WLC Ethernet links into one logical aggregation. Running OSPF on physical controller ports would not establish a controller-supported LAG or ensure suitable VLAN transport. A WLC may participate in routed architectures through other devices, but its uplink bundle requires link-aggregation compatibility. The switch should configure the relevant EtherChannel/Port-channel rather than substituting OSPF adjacencies for physical bundling.
Question 169
A point-to-point routed interface needs the specifically chosen local-link address fe80::2 for neighbor discovery. Which interface command expresses the address type?
- ipv6 address fe80::2/64
- ipv6 address fe80::2 link-local
- ipv6 address 2001:db8:0:1::2/64
- ipv6 unicast-routing in interface configuration mode
Explanation
Correct Answer
B:ipv6 address fe80::2 link-local explicitly assigns the selected IPv6 link-local address to the interface in IOS configuration mode. Such addresses support Neighbor Discovery and next-hop communication only on the attached link and are never routed between networks. This matches the exact specified local identity rather than an automatically generated address. Verify uniqueness on the link and correct interface context, especially when using link-local next hops in static IPv6 routing.
Incorrect Answers
A:The IOS syntax for explicitly setting a link-local IPv6 address on an interface uses the link-local keyword rather than simply treating it as a global unicast prefix assignment. Entering a /64 suffix is not the requested local-link form in the traditional IOS workflow. Link-local addresses have interface scope and require the correct per-interface configuration context. The engineer should specify the chosen fe80::2 address as link-local, not use a normal global-address syntax.
C:The address 2001:db8:0:1::2/64 has global-unicast-style syntax in a documentation-only example range, not the fe80::2 link-local identity requested. Configuring it could be useful in a laboratory demonstrating global-style addressing, but it would not set the intended link-local value. IPv6 interfaces can have both address types simultaneously, which makes the distinction operationally important. The question asks for one exact link-scoped address, not any valid IPv6 address.
D:ipv6 unicast-routing is an IOS global configuration control for IPv6 transit forwarding. It is not an interface command to assign the specific fe80::2 address and cannot replace link-local interface setup. A router may have IPv6 routing enabled while still choosing its own link-local address automatically. The requested behavior is manual assignment under a particular point-to-point interface, so use the appropriate ipv6 address ... link-local directive.
Question 170
A configured extended IPv4 ACL begins with permit ip 10.0.0.0 0.255.255.255 any, followed by deny tcp 10.1.1.0 0.0.0.255 any eq 23. What happens to a Telnet packet from 10.1.1.8?
- It matches the first permit and is not evaluated against the later deny
- It is denied because a deny statement always overrides a permit
- It is dropped only after reaching the implicit deny at the end
- It is transformed into SSH on TCP 22
Explanation
Correct Answer
A:Cisco IOS ACL entries are normally processed in sequence, and the first matching ACE determines the permit or deny result. The opening permit ip 10.0.0.0 0.255.255.255 any covers all IPv4 protocols from 10/8, including TCP Telnet from 10.1.1.8. Because that packet already matches the first permit, the later narrower deny is not evaluated. To block the intended traffic, put the specific deny before the broader permit.
Incorrect Answers
B:A deny ACE has no inherent global priority over a permit ACE earlier in the same sequential ACL. ACL evaluation stops at the first match, so a broad permit ip at the beginning can shadow a later deny tcp targeting a subset of that traffic. The administrator must order more specific exceptions before generic permits. Assuming all denies override permits would misunderstand rule-order semantics and could produce a misleading sense of security.
C:The implicit deny at the end of an ACL applies only if a packet reaches the end without matching an earlier ACE. Here the Telnet packet from 10.1.1.8 matches the very first permit, so it never encounters either the later explicit deny or the implicit deny. Implicit-deny behavior is important for unmatched traffic but cannot repair a shadowed rule. Inspect ACL counters and ordering to confirm which statement actually processes this flow.
D:An extended ACL decides whether matching packets are permitted or denied; it does not automatically rewrite the application protocol from Telnet on TCP port 23 to SSH on port 22. Security migration to SSH requires configuring the server and clients appropriately and potentially blocking Telnet with correctly ordered ACEs. The broad permit in this example even allows the stated Telnet flow. Rule evaluation controls acceptance, not transport conversion.